Section 1A

Graphing Linear Functions

🎯 Learning Objectives

  • Slope-intercept, point-slope, and standard forms: when to use each.
  • How to read slope and y-intercept off a graph.
  • How to find slope from any two points without making sign errors.
  • What parallel and perpendicular lines look like algebraically.
  • Strategies for matching equations to graphs.
  • Practice questions with worked solutions.

1. Three Forms of a Line

Slope-Intercept Form

y = m·x + b

Point-Slope Form

y − y₁ = m·(x − x₁)

Standard Form

A·x + B·y = C

Form

When to Use

Slope-intercept (y = mx + b)

You know slope and y-intercept; or you want to graph fast.

Point-slope

You know slope and ANY single point on the line.

Standard (Ax + By = C)

You're given an equation in this form (often word problems).

2. Slope: The 'Steepness' of a Line

Slope between two points

m = (y₂ − y₁) / (x₂ − x₁)

Slope is rise over run. Positive slope rises left-to-right; negative slope falls; zero slope is horizontal; undefined slope is vertical.

Slope

Looks Like

Example

Positive (m > 0)

Rising line ↗

y = 2x + 1

Negative (m < 0)

Falling line ↘

y = −3x + 4

Zero (m = 0)

Horizontal line :

y = 5

Undefined

Vertical line |

x = 3

3. Reading a Linear Graph

STEP 1: Find the y-intercept (where the line crosses the y-axis). That's b.

STEP 2: Pick any two clean lattice points. Compute rise/run. That's m.

STEP 3: Write the equation: y = m·x + b

4. Parallel and Perpendicular Lines

❓ Comparing two lines: what relationship?

Same slope, different y-int ▼

Slopes multiply to −1 ▼

PARALLEL (never meet)

PERPENDICULAR (90° angle)

💡 Negative Reciprocal: How to Find a Perpendicular Slope

Flip the fraction and change the sign. Slope of 2/3 → perpendicular slope is −3/2. Slope of −5 → perpendicular slope is 1/5.

📝 Example: Find the equation of a line through (4, 1) parallel to y = 3x − 7.

Step 1: Parallel → same slope. m = 3.

Step 2: Use point-slope: y − 1 = 3(x − 4)

Step 3: Simplify: y = 3x − 11

5. Strategies

⚡ STRATEGY 1: Quick check for matching equations

When matching an equation to a graph, plug x = 0 into the equation. The result is the y-intercept: see if it matches the graph.

⚡ STRATEGY 2: Slope sign test

Read the graph from left to right. A rising line has positive slope; a falling line has negative slope. Use two points when a numerical slope is needed.

⚡ STRATEGY 3: Convert standard form fast

To get slope from Ax + By = C, just compute m = −A/B. Don't waste time solving for y.

⚠️ Common Mistakes

  • Subtracting coordinates in the wrong order: always (y₂ − y₁) over (x₂ − x₁): same order!
  • Confusing parallel (same slope) with perpendicular (negative reciprocal slope).
  • Mixing up rise and run: rise is vertical (y), run is horizontal (x).
  • Forgetting that horizontal lines have slope 0, not undefined.

6. Summary

📌 Key Takeaways

  • Slope-intercept: y = m·x + b. m is slope, b is y-intercept.
  • Slope formula: m = (y₂ − y₁) / (x₂ − x₁)
  • Parallel: Same slope, different intercept.
  • Perpendicular: Slopes are negative reciprocals (product = −1).
  • Horizontal line: y = constant; slope = 0.
  • Vertical line: x = constant; slope is undefined.

7. Practice: 10 Questions

Q1. What is the slope of the line passing through (2, 3) and (6, 11)?

A) 1 B) 2 C) 3 D) 4

Hint: (11 − 3)/(6 − 2) = 8/4 = 2.

Q2. A line has equation y = −4x + 7. What is its y-intercept?

A) −4 B) 4 C) −7 D) 7

Hint: b is the constant. y-int is 7.

Q3. What is the slope of the line 3x + 2y = 12?

A) 3/2 B) −3/2 C) 2/3 D) −2/3

Hint: Use −A/B = −3/2.

Q4. Which line is parallel to y = (1/2)x + 3?

A) y = 2x + 3 B) y = −(1/2)x + 1 C) y = (1/2)x − 5 D) y = −2x + 7

Hint: Parallel = same slope (1/2).

Q5. Which line is perpendicular to y = 5x − 1?

A) y = 5x + 7 B) y = −5x + 2 C) y = (1/5)x − 1 D) y = −(1/5)x + 4

Hint: Negative reciprocal of 5 is −1/5.

Q6. A line passes through (0, −3) with slope 4. What is its equation?

A) y = 4x − 3 B) y = −3x + 4 C) y = 4x + 3 D) y = −4x − 3

Hint: y-int = −3, slope = 4: y = 4x − 3.

Q7. The line y = mx + 2 passes through (3, 8). What is m?

A) 1 B) 2 C) 3 D) 6

Hint: Plug in: 8 = 3m + 2 → m = 2.

Q8. A horizontal line passes through (5, −2). What is its equation?

A) x = 5 B) x = −2 C) y = 5 D) y = −2

Hint: Horizontal: y = constant = −2.

Q9. Two points: (−1, 4) and (3, −4). What is the slope?

A) −2 B) 2 C) −1/2 D) 1/2

Hint: (−4 − 4)/(3 − (−1)) = −8/4 = −2.

Q10. The line y = (2/3)x + b passes through (6, 7). Find b.

A) 1 B) 2 C) 3 D) 4

Hint: 7 = (2/3)(6) + b = 4 + b → b = 3.

Answer Key & Worked Solutions

#

Answer

Reasoning

Q1.

B) 2

Slope formula directly.

Q2.

D) 7

y-int = constant in slope-intercept form.

Q3.

B) −3/2

From Ax + By = C: m = −A/B.

Q4.

C) y = (1/2)x − 5

Same slope, different y-int.

Q5.

D) y = −(1/5)x + 4

Negative reciprocal of 5.

Q6.

A) y = 4x − 3

Plug into y = mx + b.

Q7.

B) 2

Substitute (3, 8) into equation.

Q8.

D) y = −2

Horizontal lines have form y = k.

Q9.

A) −2

Slope formula.

Q10.

C) 3

Plug in and solve for b.

Need personalised help?

Our expert tutors can walk you through any topic in a 1-on-1 session.

Book a Free Trial Session