SAT

Linear Inequalities Two Variables

🎯 What You'll Learn in This Lesson

  • What it means to graph an inequality in two variables.
  • When to use a solid versus dashed boundary line.
  • How to choose which side of the line to shade.
  • How to solve a SYSTEM of two-variable inequalities (the overlap region).
  • Speed tricks for matching graphs to systems.
  • 10 trick-based practice questions.

1. What Is a Two-Variable Inequality?

An equation in two variables (like y = 2x + 1) graphs as a single line. An INEQUALITY in two variables (like y ≥ 2x + 1) graphs as an entire REGION — the line plus everything on one side of it.

2. Three Steps to Graph

STEP 1 — Pretend the inequality is an equation. Graph the boundary line.

STEP 2 — SOLID line for ≤ or ≥. DASHED line for < or >.

STEP 3 — Shade the side that satisfies the inequality (use a test point).

3. The Test Point Trick

Pick any point NOT on the line — (0, 0) is usually easiest. Plug it into the original inequality. If the result is TRUE, shade the side containing that point. If FALSE, shade the OTHER side.

📝 Example: Graph y > 2x − 1

Boundary: y = 2x − 1, slope 2, y-intercept −1.

Style: Strict > → DASHED line.

Test (0, 0): 0 > 2(0) − 1 → 0 > −1 ✓ TRUE. Shade the side containing the origin (above the line).

4. Solid vs. Dashed — At a Glance

❓ Does the inequality include the boundary?

≤ or ≥ ▼

< or > ▼

SOLID line (boundary is part of solution)

DASHED line (boundary is NOT included)

5. Systems of Two-Variable Inequalities

Two inequalities graphed together create an OVERLAP region. Any (x, y) point inside the overlap satisfies both inequalities at once.

💡 Identifying the Overlap Region

Shade each inequality lightly with a different color or pattern. The DARKER region (where colors layer) is your solution set.

6. Speed Tricks

⚡ TRICK 1 — Solve for y first

Convert each inequality to y ≤ … or y ≥ … form. Then 'y ≥' means shade ABOVE; 'y ≤' means shade BELOW. Done in 5 seconds.

⚡ TRICK 2 — Origin test

If the boundary doesn't pass through (0, 0), use (0, 0) as your test point. Plug it in: if true, shade the half-plane containing the origin; if false, the other half.

⚡ TRICK 3 — Spot dashed vs. solid in answer choices

On graph-matching multiple-choice questions, the line style (solid/dashed) usually differs across choices. Knock out half the options instantly by checking the inequality symbol.

⚠️ Watch Out!

  • Drawing a dashed line for ≤ or ≥, or a solid line for < or >.
  • Shading the wrong side because of an arithmetic slip in the test point.
  • Forgetting to check that test point is NOT on the boundary line.
  • When solving for y, forgetting to flip the inequality if you divided by a negative.

7. Summary

📌 The Whole Topic in 30 Seconds

  • Boundary line: Solid for ≤ or ≥; dashed for < or >.
  • Shade: Use a test point. (0, 0) is the easiest if not on the line.
  • y ≥ form: Shade above the line.
  • y ≤ form: Shade below the line.
  • System: Solution is the overlap of all shaded regions.

8. Practice — 10 Questions

Q1. Which point is a solution to y < 2x + 1?

A) (0, 5) B) (1, 0) C) (2, 6) D) (3, 8)

Hint: Plug each in. (1, 0): 0 < 3 ✓

Q2. The boundary line of y ≥ 3x − 2 is drawn how?

A) Dashed B) Solid C) Dotted D) None

Hint: ≥ includes the boundary → solid.

Q3. Which inequality is satisfied by (0, 0)?

A) y > 2x + 5 B) y ≤ x − 3 C) y < −x + 1 D) y ≥ 4x + 2

Hint: Plug (0,0): only C gives 0 < 1 ✓

Q4. The graph of y < x has what features?

A) Solid line, shaded above B) Solid line, shaded below C) Dashed line, shaded above D) Dashed line, shaded below

Hint: <: dashed. y < x: shade below.

Q5. Which of the following is NOT a solution to y ≥ −x + 4?

A) (0, 4) B) (5, 5) C) (1, 0) D) (3, 2)

Hint: (1, 0): 0 ≥ 3 is false.

Q6. A system: y > x and y < −x + 6. Which point is in the overlap?

A) (0, 0) B) (4, 1) C) (1, 2) D) (3, 5)

Hint: (1, 2): 2 > 1 ✓ and 2 < 5 ✓

Q7. The boundary of y > 2 is drawn how?

A) Solid horizontal line at y = 2, shaded above B) Dashed horizontal line at y = 2, shaded above C) Dashed vertical line D) Solid vertical line

Hint: y > 2: dashed horizontal, shade above.

Q8. Which inequality describes 'shade below the line y = (1/2)x + 3, boundary included'?

A) y < (1/2)x + 3 B) y ≤ (1/2)x + 3 C) y > (1/2)x + 3 D) y ≥ (1/2)x + 3

Hint: 'Below' = ≤ (boundary included).

Q9. Which point satisfies BOTH 2x + y ≤ 6 AND x − y ≥ 0?

A) (0, 6) B) (3, 0) C) (1, 5) D) (4, 4)

Hint: (3, 0): 6 ≤ 6 ✓ and 3 ≥ 0 ✓

Q10. The line y = −x + 4 is dashed and shaded above. Which inequality matches?

A) y < −x + 4 B) y > −x + 4 C) y ≤ −x + 4 D) y ≥ −x + 4

Hint: Dashed → strict; shaded above → >.

Answer Key & Shortcut Solutions

#

Answer

Shortcut Reason

Q1.

B) (1, 0)

Plug into y < 2x + 1: 0 < 3 ✓

Q2.

B) Solid

≥ → boundary included → solid line.

Q3.

C) y < −x + 1

Origin: 0 < 1 ✓

Q4.

D) Dashed, below

< → dashed; y < x → below.

Q5.

C) (1, 0)

0 ≥ 3 is false.

Q6.

C) (1, 2)

Both 2 > 1 and 2 < 5 hold.

Q7.

B) Dashed, above

y > 2: dashed horizontal, shade above.

Q8.

B) y ≤ (1/2)x + 3

Below + included = ≤

Q9.

B) (3, 0)

Satisfies both.

Q10.

B) y > −x + 4

Strict + above = >

🚀 You've Got This! 💪

Two-variable inequalities are just one-variable inequalities… in 2D! Master test-point shading and you're set.

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